File Upload in C#.Net Windows Application

I have seen so many people are facing problem while uploading file in windows application.  So while development path of upload directory not found error id most common. In this article I will show you how you can upload a file in windows application using C#.Net or VB.Net.  

In my previous article I have shown you how you can Bind DataGridView In Windows Application Using C#, How to Minimize an Application to the Taskbar Tray in C#.Net | System Tray Application C#, Email Validation in Windows Application C#.Net and VB.Net | Validating Email ID in TextBox in C# .Net, Displaying More than One Month in the Windows Forms MonthCalendar Control Using C#.Net.

So for this article first we will create a new windows application and add a form. In this form we will add a textbox and two button controls. One button control to browse the file and other one is for uploading the file.

Now here is the layout for the form.

Now in this form add an openfiledialog control. This control we will use for open the file select window.

Now open the code file and add the below code.

C#.Net

using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; namespace DemoWindowsApplication {     public partial class FileUpload : Form     {         public FileUpload()         {             InitializeComponent();         }         private void button1_Click(object sender, EventArgs e)         {             DialogResult result = openFileDialog1.ShowDialog();             if (result == DialogResult.OK) // Test result.             {                 textBox1.Text = openFileDialog1.FileName;             }         }         private void button2_Click(object sender, EventArgs e)         {             int count = 0;             string[] FilenameName;             foreach (string item in openFileDialog1.FileNames)             {                 FilenameName = item.Split('\\');                 File.Copy(item, @"Images\" + FilenameName[FilenameName.Length - 1]);                 count++;             }             MessageBox.Show(Convert.ToString(count) + " File(s) copied");         }     } }

VB.Net

Imports System Imports System.Collections.Generic Imports System.ComponentModel Imports System.Data Imports System.Drawing Imports System.Linq Imports System.Text Imports System.Windows.Forms Imports System.IO Namespace DemoWindowsApplication     Partial Public Class FileUpload         Inherits Form         Public Sub New()             InitializeComponent()         End Sub         Private Sub button1_Click(ByVal sender As Object, ByVal e As EventArgs)             Dim result As DialogResult = openFileDialog1.ShowDialog()             If result = DialogResult.OK Then                 ' Test result.                 textBox1.Text = openFileDialog1.FileName             End If         End Sub         Private Sub button2_Click(ByVal sender As Object, ByVal e As EventArgs)             Dim count As Integer = 0             Dim FilenameName As String()             For Each item As String In openFileDialog1.FileNames                 FilenameName = item.Split("\"c)                 File.Copy(item, "Images\" + FilenameName(FilenameName.Length - 1))                 System.Math.Max(System.Threading.Interlocked.Increment(count), count - 1)             Next             MessageBox.Show(Convert.ToString(count) + " File(s) copied")         End Sub     End Class End Namespace

In above code we have used below mention code for uploading the file

private void button2_Click(object sender, EventArgs e)         {             int count = 0;             string[] FilenameName;             foreach (string item in openFileDialog1.FileNames)             {                 FilenameName = item.Split('\\');                 File.Copy(item, @"Images\" + FilenameName[FilenameName.Length - 1]);                 count++;             }             MessageBox.Show(Convert.ToString(count) + " File(s) copied");         }

Now run the application by putting break point on upload button click event. Now here we will see that we are facing an error message that “Upload file path not found”.  Please check the below image.

This is the most common error faced by developer while developing the file upload in windows application.

Now we will check out bin directory. In this directory we are not having images folder.

 

So we will create image folder in our bind directory.

Now again run the application and try to upload the file. File will upload successfully.

Now again check the images directory in bin folder. You will get the uploaded file.

DOWNLOAD